5x^2-93x-98=0

Solution for 5x^2-93x-98=0 equation:

5x^2-93x-98=0

a = 5; b = -93; c = -98;
Δ = b2-4ac
Δ = -932-4·5·(-98)
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10609}=103$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-93)-103}{2*5}=\frac{-10}{10}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-93)+103}{2*5}=\frac{196}{10}
=19+3/5
$